std::equal_range
Defined in header <algorithm>
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(1) | ||
template< class ForwardIt, class T > std::pair<ForwardIt, ForwardIt> |
(until C++20) | |
template< class ForwardIt, class T > constexpr std::pair<ForwardIt, ForwardIt> |
(since C++20) | |
(2) | ||
template< class ForwardIt, class T, class Compare > std::pair<ForwardIt, ForwardIt> |
(until C++20) | |
template< class ForwardIt, class T, class Compare > constexpr std::pair<ForwardIt, ForwardIt> |
(since C++20) | |
Returns a range containing all elements equivalent to value in the range [
first,
last)
.
The range [
first,
last)
must be at least partially ordered with respect to value, i.e. it must satisfy all of the following requirements:
- partitioned with respect to element < value or comp(element, value) (that is, all elements for which the expression is true precedes all elements for which the expression is false)
- partitioned with respect to !(value < element) or !comp(value, element)
- for all elements, if element < value or comp(element, value) is true then !(value < element) or !comp(value, element) is also true
A fully-sorted range meets these criteria.
The returned range is defined by two iterators, one pointing to the first element that is not less than value and another pointing to the first element greater than value. The first iterator may be alternatively obtained with std::lower_bound(), the second - with std::upper_bound().
The first version uses operator< to compare the elements, the second version uses the given comparison function comp.
Parameters
first, last | - | the range of elements to examine |
value | - | value to compare the elements to |
comp | - | binary predicate which returns true if the first argument is less than (i.e. is ordered before) the second. The signature of the predicate function should be equivalent to the following: bool pred(const Type1 &a, const Type2 &b); While the signature does not need to have const &, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) |
Type requirements | ||
-ForwardIt must meet the requirements of LegacyForwardIterator.
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-Compare must meet the requirements of BinaryPredicate. It is not required to satisfy Compare.
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Return value
A std::pair containing a pair of iterators defining the wanted range. The first pointing to the first element that is not less than value and the second pointing to the first element greater than value.
If there are no elements not less than value, last is returned as the first element. Similarly if there are no elements greater than value, last is returned as the second element.
Complexity
The number of comparisons performed is logarithmic in the distance between first and last (At most 2 * log
2(last - first) + O(1) comparisons). However, for non-LegacyRandomAccessIterators, the number of iterator increments is linear. Notably, std::set and std::multiset iterators are not random access, and so their member functions std::set::equal_range (resp. std::multiset::equal_range) should be preferred.
Possible implementation
equal_range (1) |
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template<class ForwardIt, class T> std::pair<ForwardIt, ForwardIt> equal_range(ForwardIt first, ForwardIt last, const T& value) { return std::make_pair(std::lower_bound(first, last, value), std::upper_bound(first, last, value)); } |
equal_range (2) |
template<class ForwardIt, class T, class Compare> std::pair<ForwardIt, ForwardIt> equal_range(ForwardIt first, ForwardIt last, const T& value, Compare comp) { return std::make_pair(std::lower_bound(first, last, value, comp), std::upper_bound(first, last, value, comp)); } |
Example
#include <algorithm> #include <iostream> #include <vector> struct S { int number; char name; // note: name is ignored by this comparison operator bool operator<(const S& s) const { return number < s.number; } }; struct Comp { bool operator()(const S& s, int i) const { return s.number < i; } bool operator()(int i, const S& s) const { return i < s.number; } }; int main() { // note: not ordered, only partitioned w.r.t. S defined below const std::vector<S> vec {{1, 'A'}, {2, 'B'}, {2, 'C'}, {2, 'D'}, {4, 'G'}, {3, 'F'}}; const S value {2, '?'}; std::cout << "Compare using S::operator<(): "; const auto p = std::equal_range(vec.begin(), vec.end(), value); for (auto i = p.first; i != p.second; ++i) std::cout << i->name << ' '; std::cout << "\n" "Using heterogeneous comparison: "; const auto p2 = std::equal_range(vec.begin(), vec.end(), 2, Comp{}); for (auto i = p2.first; i != p2.second; ++i) std::cout << i->name << ' '; }
Output:
Compare using S::operator<(): B C D Using heterogeneous comparison: B C D
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 270 | C++98 | Compare was required to satisfy Compare and T was requiredto be LessThanComparable (strict weak ordering required) |
only a partitioning is required; heterogeneous comparisons permitted |
LWG 384 | C++98 | at most 2 * log(last - first) + 1 comparisons were allowed, which is not implementable[1] |
corrected to 2 * log 2(last - first) + O(1) |
- ↑ Applying
equal_range
to a single-element range requires 2 comparisons, but at most 1 comparison is allowed by the complexity requirement.
See also
returns an iterator to the first element not less than the given value (function template) | |
returns an iterator to the first element greater than a certain value (function template) | |
determines if an element exists in a partially-ordered range (function template) | |
divides a range of elements into two groups (function template) | |
determines if two sets of elements are the same (function template) | |
returns range of elements matching a specific key (public member function of std::set<Key,Compare,Allocator> ) | |
returns range of elements matching a specific key (public member function of std::multiset<Key,Compare,Allocator> ) | |
(C++20) |
returns range of elements matching a specific key (niebloid) |