std::ranges::end
Defined in header <ranges>
|
||
inline namespace /* unspecified */ { inline constexpr /* unspecified */ end = /* unspecified */; |
(since C++20) (customization point object) |
|
Call signature |
||
template< class T > requires /* see below */ |
(since C++20) | |
Returns a sentinel indicating the end of a range.
If the argument is an lvalue or ranges::enable_borrowed_range<std::remove_cv_t<T>> is true, then a call to ranges::end
is expression-equivalent to:
- t + std::extent_v<T> if t has an array type of known bound.
- If std::remove_all_extents_t<std::remove_reference_t<T>> is incomplete, then the call to
ranges::end
is ill-formed, no diagnostic required.
- If std::remove_all_extents_t<std::remove_reference_t<T>> is incomplete, then the call to
- Otherwise, decay-copy(t.end()) (until C++23)auto(t.end()) (since C++23), if that expression is valid, and its type models std::sentinel_for<ranges::iterator_t<T>>.
- Otherwise, decay-copy(end(t)) (until C++23)auto(end(t)) (since C++23), if
T
is a class or enumeration type, that expression is valid and its converted type models std::sentinel_for<ranges::iterator_t<T>>, where the overload resolution is performed with the following candidates:- any declarations of
end
found by argument-dependent lookup. - void end(auto&) = delete;
- void end(const auto&) = delete;
- any declarations of
In all other cases, a call to ranges::end
is ill-formed, which can result in substitution failure when the call to ranges::end
appears in the immediate context of a template instantiation.
Customization point objects
The name ranges::end
denotes a customization point object, which is a const function object of a literal semiregular
class type. For exposition purposes, the cv-unqualified version of its type is denoted as __end_fn
.
All instances of __end_fn
are equal. The effects of invoking different instances of type __end_fn
on the same arguments are equivalent, regardless of whether the expression denoting the instance is an lvalue or rvalue, and is const-qualified or not (however, a volatile-qualified instance is not required to be invocable). Thus, ranges::end
can be copied freely and its copies can be used interchangeably.
Given a set of types Args...
, if std::declval<Args>()... meet the requirements for arguments to ranges::end
above, __end_fn
models
- std::invocable<__end_fn, Args...>,
- std::invocable<const __end_fn, Args...>,
- std::invocable<__end_fn&, Args...>, and
- std::invocable<const __end_fn&, Args...>.
Otherwise, no function call operator of __end_fn
participates in overload resolution.
Notes
If the argument is an rvalue (i.e. T
is an object type) and ranges::enable_borrowed_range<std::remove_cv_t<T>> is false, or if it is of an array type of unknown bound, the call to ranges::end
is ill-formed, which also results in substitution failure.
If ranges::end(std::forward<T>(t)) is valid, then decltype(ranges::end(std::forward<T>(t))) and decltype(ranges::begin(std::forward<T>(t))) model std::sentinel_for in all cases, while T
models std::ranges::range.
The C++20 standard requires that if the underlying end
function call returns a prvalue, the return value is move-constructed from the materialized temporary object. All implementations directly return the prvalue instead. The requirement is corrected by the post-C++20 proposal P0849R8 to match the implementations.
Example
#include <algorithm> #include <iostream> #include <ranges> #include <vector> int main() { std::vector<int> vec{3, 1, 4}; if (std::ranges::find(vec, 5) != std::ranges::end(vec)) std::cout << "found a 5 in vector vec!\n"; int arr[]{5, 10, 15}; if (std::ranges::find(arr, 5) != std::ranges::end(arr)) std::cout << "found a 5 in array arr!\n"; }
Output:
found a 5 in array arr!
See also
(C++20) |
returns a sentinel indicating the end of a read-only range (customization point object) |
(C++20) |
returns an iterator to the beginning of a range (customization point object) |
(C++11)(C++14) |
returns an iterator to the end of a container or array (function template) |