C++ named requirements: LiteralType (since C++11)
From cppreference.com
Specifies that a type is a literal type. Literal types are the types of constexpr
variables and they can be constructed, manipulated, and returned from constexpr
functions.
Note: the standard doesn't define a named requirement with this name. This is a type category defined by the core language. It is included here as a named requirement only for consistency.
Requirements
A literal type is any of the following:
|
(since C++14) |
- scalar type;
- reference type;
- an array of literal type;
- possibly cv-qualified class type that has all of the following properties:
- has a trivial (until C++20)
constexpr
(since C++20) destructor, - is one of
- has a trivial (until C++20)
|
(since C++17) |
- an aggregate union type that
- has no variant members, or
- has at least one variant member of non-volatile literal type,
- a non-union aggregate type, and each of its anonymous union members
- has no variant members, or
- has at least one variant member of non-volatile literal type,
- a type with at least one
constexpr
(possibly template) constructor that is not a copy or move constructor,
Notes
A type can be literal even if all of its constexpr constructors are deleted, inaccessible, or cannot participate in overload resolution.
struct A { constexpr A(int) = delete; char c; }; // A is a literal type constexpr A v = std::bit_cast<A>('0'); // OK in C++20 // v has literal type and thus can be constexpr
Example
Literal type that extends string literals:
Run this code
#include <cstddef> #include <iostream> #include <stdexcept> class conststr // conststr is a literal type { const char* p; std::size_t sz; public: template<std::size_t N> constexpr conststr(const char(&a)[N]) : p(a), sz(N - 1) {} constexpr char operator[](std::size_t n) const { return n < sz ? p[n] : throw std::out_of_range(""); } constexpr std::size_t size() const { return sz; } }; constexpr std::size_t count_lower(conststr s) { std::size_t c{}; for (std::size_t n{}; n != s.size(); ++n) if ('a' <= s[n] && s[n] <= 'z') ++c; return c; } // An output function that requires a compile-time constant N, for testing template<int N> struct constN { constN() { std::cout << N << '\n'; } }; int main() { std::cout << "the number of lowercase letters in \"Hello, world!\" is "; constN<count_lower("Hello, world!")>(); // the string literal is implicitly // converted to conststr }
Output:
the number of lowercase letters in "Hello, world!" is 9
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
CWG 1453 | C++11 | a literal class could have volatile data members | not allowed |
CWG 1951 | C++11 C++14 |
it was unclear whether cv-qualified void (C++14) and class types (C++11) are literal types |
they are |
CWG 2096 | C++11 | for a union type to be literal, all its non- static data members must be literal |
only one non-static data member needs to be |
CWG 2598 | C++11 | for a union type to be literal, it must have at least one non-static data member |
it can have no non- static data member |
See also
(C++11)(deprecated in C++17)(removed in C++20) |
checks if a type is a literal type (class template) |