std::remove_reference
From cppreference.com
Defined in header <type_traits>
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||
template< class T > struct remove_reference; |
(since C++11) | |
If the type T
is a reference type, provides the member typedef type
which is the type referred to by T
. Otherwise type
is T
.
The behavior of a program that adds specializations for std::remove_reference
is undefined.
Member types
Name | Definition |
type
|
the type referred by T or T if it is not a reference
|
Helper types
template< class T > using remove_reference_t = typename remove_reference<T>::type; |
(since C++14) | |
Possible implementation
template<class T> struct remove_reference { typedef T type; }; template<class T> struct remove_reference<T&> { typedef T type; }; template<class T> struct remove_reference<T&&> { typedef T type; }; |
Example
Run this code
#include <iostream> #include <type_traits> int main() { std::cout << std::boolalpha; std::cout << "std::remove_reference<int>::type is int? " << std::is_same<int, std::remove_reference<int>::type>::value << '\n'; std::cout << "std::remove_reference<int&>::type is int? " << std::is_same<int, std::remove_reference<int&>::type>::value << '\n'; std::cout << "std::remove_reference<int&&>::type is int? " << std::is_same<int, std::remove_reference<int&&>::type>::value << '\n'; std::cout << "std::remove_reference<const int&>::type is const int? " << std::is_same<const int, std::remove_reference<const int&>::type>::value << '\n'; }
Output:
std::remove_reference<int>::type is int? true std::remove_reference<int&>::type is int? true std::remove_reference<int&&>::type is int? true std::remove_reference<const int&>::type is const int? true
See also
(C++11) |
checks if a type is either an lvalue reference or rvalue reference (class template) |
(C++11)(C++11) |
adds an lvalue or rvalue reference to the given type (class template) |
(C++20) |
combines std::remove_cv and std::remove_reference (class template) |