std::is_lvalue_reference
From cppreference.com
Defined in header <type_traits>
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template< class T > struct is_lvalue_reference; |
(since C++11) | |
std::is_lvalue_reference
is an UnaryTypeTrait.
Checks whether T
is an lvalue reference type. Provides the member constant value
which is equal to true, if T
is an lvalue reference type. Otherwise, value
is equal to false.
The behavior of a program that adds specializations for std::is_lvalue_reference
or std::is_lvalue_reference_v
(since C++17) is undefined.
Template parameters
T | - | a type to check |
Helper variable template
template< class T > inline constexpr bool is_lvalue_reference_v = is_lvalue_reference<T>::value; |
(since C++17) | |
Inherited from std::integral_constant
Member constants
value [static] |
true if T is an lvalue reference type, false otherwise (public static member constant) |
Member functions
operator bool |
converts the object to bool, returns value (public member function) |
operator() (C++14) |
returns value (public member function) |
Member types
Type | Definition |
value_type
|
bool |
type
|
std::integral_constant<bool, value> |
Possible implementation
template<class T> struct is_lvalue_reference : std::false_type {}; template<class T> struct is_lvalue_reference<T&> : std::true_type {}; |
Example
Run this code
#include <iostream> #include <type_traits> class A {}; int main() { std::cout << std::boolalpha; std::cout << std::is_lvalue_reference<A>::value << '\n'; std::cout << std::is_lvalue_reference<A&>::value << '\n'; std::cout << std::is_lvalue_reference<A&&>::value << '\n'; std::cout << std::is_lvalue_reference<int>::value << '\n'; std::cout << std::is_lvalue_reference<int&>::value << '\n'; std::cout << std::is_lvalue_reference<int&&>::value << '\n'; }
Output:
false true false false true false
See also
(C++11) |
checks if a type is either an lvalue reference or rvalue reference (class template) |
(C++11) |
checks if a type is an rvalue reference (class template) |