std::is_compound
From cppreference.com
Defined in header <type_traits>
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||
template< class T > struct is_compound; |
(since C++11) | |
std::is_compound
is an UnaryTypeTrait.
If T
is a compound type (that is, array, function, object pointer, function pointer, member object pointer, member function pointer, reference, class, union, or enumeration, including any cv-qualified variants), provides the member constant value
equal true. For any other type, value
is false.
The behavior of a program that adds specializations for std::is_compound
or std::is_compound_v
(since C++17) is undefined.
Template parameters
T | - | a type to check |
Helper variable template
template< class T > inline constexpr bool is_compound_v = is_compound<T>::value; |
(since C++17) | |
Inherited from std::integral_constant
Member constants
value [static] |
true if T is a compound type, false otherwise (public static member constant) |
Member functions
operator bool |
converts the object to bool, returns value (public member function) |
operator() (C++14) |
returns value (public member function) |
Member types
Type | Definition |
value_type
|
bool |
type
|
std::integral_constant<bool, value> |
Notes
Compound types are the types that are constructed from fundamental types. Any C++ type is either fundamental or compound.
Possible implementation
template<class T> struct is_compound : std::integral_constant<bool, !std::is_fundamental<T>::value> {}; |
Example
Run this code
#include <type_traits> static_assert(not std::is_compound_v<int>); static_assert(std::is_compound_v<int*>); static_assert(std::is_compound_v<int&>); void f(); static_assert(std::is_compound_v<decltype(f)>); static_assert(std::is_compound_v<decltype(&f)>); static_assert(std::is_compound_v<char['a']>); class C {}; static_assert(std::is_compound_v<C>); union U {}; static_assert(std::is_compound_v<U>); enum struct E { e }; static_assert(std::is_compound_v<E>); static_assert(std::is_compound_v<decltype(E::e)>); struct S { int i : 8; int j; void foo(); }; static_assert(not std::is_compound_v<decltype(S::i)>); static_assert(not std::is_compound_v<decltype(S::j)>); static_assert(std::is_compound_v<decltype(&S::j)>); static_assert(std::is_compound_v<decltype(&S::foo)>); int main() {}
See also
(C++11) |
checks if a type is a fundamental type (class template) |
(C++11) |
checks if a type is a scalar type (class template) |
(C++11) |
checks if a type is an object type (class template) |
(C++11) |
checks if a type is an array type (class template) |