std::remove_pointer
From cppreference.com
Defined in header <type_traits>
|
||
template< class T > struct remove_pointer; |
(since C++11) | |
Provides the member typedef type
which is the type pointed to by T
, or, if T
is not a pointer, then type
is the same as T
.
The behavior of a program that adds specializations for std::remove_pointer
is undefined.
Member types
Name | Definition |
type
|
the type pointed to by T or T if it's not a pointer
|
Helper types
template< class T > using remove_pointer_t = typename remove_pointer<T>::type; |
(since C++14) | |
Possible implementation
template<class T> struct remove_pointer { typedef T type; }; template<class T> struct remove_pointer<T*> { typedef T type; }; template<class T> struct remove_pointer<T* const> { typedef T type; }; template<class T> struct remove_pointer<T* volatile> { typedef T type; }; template<class T> struct remove_pointer<T* const volatile> { typedef T type; }; |
Example
Run this code
#include <type_traits> static_assert ( std::is_same_v<int, int> == true && std::is_same_v<int, int*> == false && std::is_same_v<int, int**> == false && std::is_same_v<int, std::remove_pointer_t<int>> == true && std::is_same_v<int, std::remove_pointer_t<int*>> == true && std::is_same_v<int, std::remove_pointer_t<int**>> == false && std::is_same_v<int, std::remove_pointer_t<int* const>> == true && std::is_same_v<int, std::remove_pointer_t<int* volatile>> == true && std::is_same_v<int, std::remove_pointer_t<int* const volatile>> == true ); int main() {}
See also
(C++11) |
checks if a type is a pointer type (class template) |
(C++11) |
adds a pointer to the given type (class template) |