std::ranges::stride_view<V>::iterator<Const>::operator++,--,+=,-=
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< cpp | ranges | stride view | iterator
constexpr /*iterator*/& operator++(); |
(1) | (since C++23) |
constexpr void operator++( int ); |
(2) | (since C++23) |
constexpr /*iterator*/ operator++( int ) requires ranges::forward_range<Base>; |
(3) | (since C++23) |
constexpr /*iterator*/& operator--() requires ranges::bidirectional_range<Base>; |
(4) | (since C++23) |
constexpr /*iterator*/ operator--( int ) requires ranges::bidirectional_range<Base>; |
(5) | (since C++23) |
constexpr /*iterator*/& operator+=( difference_type n ) requires ranges::random_access_range<Base>; |
(6) | (since C++23) |
constexpr /*iterator*/& operator-=( difference_type n ) requires ranges::random_access_range<Base>; |
(7) | (since C++23) |
Increments or decrements the iterator.
Let current_
, end_
, stride_
, and missing_
be the data members of the iterator.
1) Equivalent to
Before the call
missing_ = ranges::advance(current_, stride_, end_); return *this
current_
should not be equal to end_
.2) Equivalent to ++*this;.
3) Equivalent to auto tmp = *this; ++*this; return tmp;.
4) Equivalent to
ranges::advance(current_, missing_ - stride_); missing_ = 0; return *this;
5) Equivalent to auto tmp = *this; --*this; return tmp;.
6) Equivalent to
if (n > 0) { ranges::advance(current_, stride_ * (n - 1)); missing_ = ranges::advance(current_, stride_, end_); } else if (n < 0) { ranges::advance(current_, stride_ * n + missing_); missing_ = 0; } return *this;
If n > 0, then before the call to this function the ranges::distance(current_, end_) must be greater than stride_ * (n - 1).
Note that if n < 0, the ranges::distance(current_, end_) is always greater than (non-positive) stride_ * (n - 1).7) Equivalent to return *this += -n;
Parameters
n | - | position relative to current location |
Return value
1,4,6,7) *this
2) (none)
3,5) a copy of *this that was made before the change
Example
This section is incomplete Reason: no example |
See also
(C++23) |
performs iterator arithmetic (function) |