std::chrono::year_month_weekday::operator sys_days, std::chrono::year_month_weekday::operator local_days
From cppreference.com
< cpp | chrono | year month weekday
constexpr operator std::chrono::sys_days() const noexcept; |
(1) | (since C++20) |
constexpr explicit operator std::chrono::local_days() const noexcept; |
(2) | (since C++20) |
Converts *this
to a std::chrono::time_point representing the same date as this year_month_weekday
.
1) If year().ok() && month().ok() && weekday().ok():
- If index() == 0, returns a
sys_days
that represents the date 7 days prior to the first weekday() of the year and month. - Else, returns a
sys_days
that represents the date (index() - 1) * 7 days after the first weekday() of the year and month.
- If index() == 0, returns a
Otherwise, the returned value is unspecified.
2) Same as (1), but returns
local_days
instead of sys_days
. Equivalent to local_days(sys_days(*this).time_since_epoch()).Example
Run this code
#include <iostream> #include <chrono> using namespace std::chrono; int main() { std::cout << std::boolalpha; constexpr auto ymwd {Tuesday[2]/11/2021}; // convert from field-based to serial-based to add hours constexpr auto sd = sys_days{ymwd} + 24h; constexpr auto ymd = floor<days>(sd); std::cout << (ymd == November/10/2021) << '\n'; }
Output:
true