std::chrono::year_month::operator+=, std::chrono::year_month::operator-=
From cppreference.com
< cpp | chrono | year month
constexpr std::chrono::year_month& operator+=( const std::chrono::years& dy ) const noexcept; |
(1) | (since C++20) |
constexpr std::chrono::year_month& operator+=( const std::chrono::months& dm ) const noexcept; |
(2) | (since C++20) |
constexpr std::chrono::year_month& operator-=( const std::chrono::years& dy ) const noexcept; |
(3) | (since C++20) |
constexpr std::chrono::year_month& operator-=( const std::chrono::months& dm ) const noexcept; |
(4) | (since C++20) |
Modifies the time point *this represents by the duration dy
or dm
.
1) Equivalent to *this = *this + dy;
2) Equivalent to *this = *this + dm;
3) Equivalent to *this = *this - dy;
4) Equivalent to *this = *this - dm;
For durations that are convertible to both std::chrono::years and std::chrono::months, the years
overloads (1,3) are preferred if the call would otherwise be ambiguous.
Example
Run this code
#include <iostream> #include <chrono> int main() { std::cout << std::boolalpha; auto ym {std::chrono::day(1)/7/2023}; ym -= std::chrono::years {2}; std::cout << (ym.month() == std::chrono::July) << ' ' << (ym.year() == std::chrono::year(2021)) << ' '; ym += std::chrono::months {7}; std::cout << (ym.month() == std::chrono::month(2)) << ' ' << (ym.year() == std::chrono::year(2022)) << '\n'; }
Output:
true true true true
See also
(C++20) |
performs arithmetic on year_month (function) |