std::chrono::tai_clock::now
From cppreference.com
static std::chrono::time_point<std::chrono::tai_clock> now(); |
(since C++20) | |
Returns a time point representing the current point in time. The result is calculated as if by std::chrono::tai_clock::from_utc(std::chrono::utc_clock::now()). Implementations may use a more accurate value of TAI time.
Parameters
(none)
Return value
A time point representing the current time.
Example
Run this code
#include <iostream> #include <iomanip> #include <vector> #include <numeric> #include <chrono> volatile int sink; int main() { std::cout << std::fixed << std::setprecision(9) << std::left; for (auto size = 1ull; size < 1000'000'000ull; size *= 100) { // record start time auto start = std::chrono::tai_clock::now(); // do some work std::vector<int> v(size, 42); sink = std::accumulate(v.begin(), v.end(), 0u); // make sure it's a side effect // record end time auto end = std::chrono::tai_clock::now(); std::chrono::duration<double> diff = end - start; std::cout << "Time to fill and iterate a vector of " << std::setw(9) << size << " ints : " << diff.count() << " s\n"; } }
Possible output:
Time to fill and iterate a vector of 1 ints : 0.000006568 s Time to fill and iterate a vector of 100 ints : 0.000002854 s Time to fill and iterate a vector of 10000 ints : 0.000116290 s Time to fill and iterate a vector of 1000000 ints : 0.011742752 s Time to fill and iterate a vector of 100000000 ints : 0.505534949 s