std::move_iterator<Iter>::operator=
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< cpp | iterator | move iterator
template< class U > move_iterator& operator=( const move_iterator<U>& other ); |
(until C++17) | |
template< class U > constexpr move_iterator& operator=( const move_iterator<U>& other ); |
(since C++17) | |
The underlying iterator is assigned the value of the underlying iterator of other, i.e. other.base().
The behavior is undefined if U is not convertible to Iter .
|
(until C++20) |
This overload participates in overload resolution only if |
(since C++20) |
Parameters
other | - | iterator adaptor to assign |
Return value
*this
Example
This section is incomplete Reason: no example |
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 3435 | C++20 | the converting assignment operator was not constrained | constrained |
See also
(C++11) |
constructs a new iterator adaptor (public member function) |