std::move_iterator<Iter>::base
From cppreference.com
< cpp | iterator | move iterator
(1) | ||
iterator_type base() const; |
(since C++11) (until C++17) |
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constexpr iterator_type base() const; |
(since C++17) (until C++20) |
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constexpr const iterator_type& base() const& noexcept; |
(since C++20) | |
constexpr iterator_type base() &&; |
(2) | (since C++20) |
Returns the underlying base iterator.
1) Copy constructs the return value from the underlying iterator.
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(until C++20) |
1) Returns a reference to the underlying iterator.
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(since C++20) |
2) Move constructs the return value from the underlying iterator.
Parameters
(none)
Return value
1) A copy of the underlying iterator.
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(until C++20) |
1) A reference to the underlying iterator.
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(since C++20) |
2) An iterator move constructed from the underlying iterator.
Exceptions
May throw implementation-defined exceptions.
Example
Run this code
#include <algorithm> #include <iostream> #include <iterator> #include <vector> int main() { std::vector<int> v{ 0, 1, 2, 3, 4 }; std::move_iterator<std::vector<int>::reverse_iterator> m1{ v.rbegin() }, m2{ v.rend() }; std::copy(m1.base(), m2.base(), std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; }
Output:
4 3 2 1 0
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 3391 | C++20 | the const version of base returns a copy of the underlying iterator
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returns a reference |
LWG 3593 | C++20 | the const version of base returns a reference but might not be noexcept
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made noexcept |
See also
(C++11)(C++11)(deprecated in C++20) |
accesses the pointed-to element (public member function) |