std::common_with
Defined in header <concepts>
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||
template <class T, class U> concept common_with = |
(since C++20) | |
The concept common_with<T, U>
specifies that two types T
and U
share a common type (as computed by std::common_type_t) to which both can be converted.
Semantic requirements
T and U model std::common_with<T, U> only if, given equality-preserving expressions t1
, t2
, u1
and u2
such that decltype((t1)) and decltype((t2)) are both T
and decltype((u1)) and decltype((u2)) are both U
,
- std::common_type_t<T, U>(t1) equals std::common_type_t<T, U>(t2) if and only if
t1
equalst2
; and - std::common_type_t<T, U>(u1) equals std::common_type_t<T, U>(u2) if and only if
u1
equalsu2
.
In other words, the conversion to the common type must preserve equality.
Equality preservation
Expressions declared in requires-expressions of the standard library concepts are required to be equality-preserving (except where stated otherwise).
See also
(C++11) |
determines the common type of a group of types (class template) |
determines the common reference type of a group of types (class template) | |
(C++20) |
specifies that two types share a common reference type (concept) |