std::deque<T,Allocator>::pop_back
From cppreference.com
void pop_back(); |
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Removes the last element of the container.
Calling pop_back
on an empty container results in undefined behavior.
Iterators and references to the erased element are invalidated. The end() iterator is also invalidated. Other references and iterators are not affected.
Parameters
(none)
Return value
(none)
Complexity
Constant.
Exceptions
Throws nothing.
Example
Run this code
#include <deque> #include <iostream> template<typename T> void print(T const & xs) { std::cout << "[ "; for(auto const& x : xs) std::cout << x << ' '; std::cout << "]\n"; } int main() { std::deque<int> numbers; print(numbers); numbers.push_back(5); numbers.push_back(3); numbers.push_back(4); print(numbers); numbers.pop_back(); print(numbers); }
Output:
[ ] [ 5 3 4 ] [ 5 3 ]
See also
removes the first element (public member function) | |
adds an element to the end (public member function) |