std::experimental::filesystem::path::root_path
From cppreference.com
< cpp | experimental | fs | path
| path root_path() const; |
(filesystem TS) | |
Returns the root path of the path. If the path does not include root path, returns path().
Effectively, returns the following: root_name() / root_directory()
Parameters
(none)
Return value
The root path of the path.
Exceptions
May throw implementation-defined exceptions.
Example
Run this code
#include <experimental/filesystem> #include <iostream> namespace fs = std::experimental::filesystem; int main() { std::cout << "Current root path is: " << fs::current_path().root_path() << '\n'; }
Possible output:
Current root path is: "C:\"
See also
| returns the root-name of the path, if present (public member function) | |
| returns the root directory of the path, if present (public member function) |